PC Electronics Plus 3/PC Electronics Plus 3.iso/dcsolve/power.bas

QuickBASIC Tokenized Source | 1991-01-01 | 10KB | 143 lines

BOARD;
PLACE
START
VSRPTR
ENERGY
THENLINE
LOADING DATA PLEASE WAIT ...."
1 HORSEPOWER = 746 WATTSd
EFFICIENCY (EFF) = POWER OUT / POWER IN"d
ENERGY = POWER x TIME = KILOWATT-HOURS (KWH)d
R = E"
R = P / I"
E =  PR"d
E = P / I"d
I = P / E"d!
I =  P / Rd%
P = EId)
P = I"
P = E"
WHAT IS THE MAXIMUM CURRENT THAT A 10K
, .5W RESISTOR CAN HANDLE WITHOUT
OVERHEATING ?"
 =  .5 / 10000
 = 7mA
WHAT MAXIMUM VOLTAGE CAN BE SAFELY CONNECTED ACROSS A 680
, 1 WATT RESISTOR ?"
 = 1 x 680
 = 26.07V"
A STANDARD HOUSEHOLD CIRCUIT HAS A MAXIMUM POWER CAPABILITY OF 2.34KW. WIRE"
SIZE LIMITS THE CURRENT TO 20A. WHAT IS THE MINIMUM LOAD RESISTANCE ?"
 = 2340 / 400 = 5.85
A CERTAIN RELAY COIL HAS A RESISTANCE OF 750
 AND REQUIRES 32 mA TO ENERGIZE."
HOW MUCH POWER IS CONSUMED BY THE RELAY ?"
 = (.032)"
 750 = .77W"
A 230V CIRCUIT IS PROTECTED BY A 60A CIRCUIT BREAKER. HOW MUCH POWER CAN
THE CIRCUIT DELIVER TO A LOAD ?"
 = 230 x 60 = 13.8KW
WHAT IS THE RESISTANCE OF A 120V, 25W HEATING ELEMENT ?"
 = 120
 / 25 = 576
AT WHAT VOLTAGE MUST A 55W SOLDERING IRON OPERATE IF IT DRAWS .47A ?
 = 55 / .47 = 117V
A DISHWASHER OPERATES FROM A 110V SOURCE. IT IS RATED AT 1.5KW BY THE
MANUFACTURER. HOW MUCH CURRENT WILL IT TAKE ?"
 = 1500 / 110 = 13.6A"
WHAT IS THE MINUMUM POWER RATING OF A 5.6K
 RESISTOR THAT HAS A VOLTAGE"
DROP OF 50V ACROSS IT ?"
 = 50"
 / 5600 = .446W"
THE OPERATING RESISTANCE OF AN ORDINARY 120V, 150W LIGHT BULB IS 96
OHMMETER WOULD READ ( 16
, 120
RESISTANCE IS LOWER AT ROOM TEMPERATURE.
A LOUDSPEAKER PRODUCES .35W OF USEFUL SOUND AND THROWS OFF 15W OF WASTE"
HEAT. WHAT IS THE SPEAKER EFFICIENCY ?
EFF = .35 / ?"
 = .35 / 15.35 = 2.35%
AN ELECTRIC MOTOR OPERATES 8 HOURS A DAY, 20 DAYS A MONTH, AT AN OUTPUT OF
20 HP. CALCULATE THE COST AT A BILLING RATE OF 1.5 CENTS PER KWH."
COST = 20 x ? x 160 x 1.5"
 = $35.80"
A AUTOMOBILE STARTER MOTOR DEVELOPS 1.25 HP AT 80% EFFICIENCY. WHAT"
CURRENT DOES IT DRAW FROM  A 12 V BATTERY ?"
I = ? x 746 x 1.25 / 12"
 = 62.1 AMPS
WHAT IS THE COST OF OPERATING FIVE 100-WATT LIGHT BULBS, 10 HOURS EACH
DAY FOR 30 DAYS AT AN ENERGY RATE OF $.0155 PER KWH ?"
COST = ? x 300 x $.0155"
 = $2.32
AN ELECTRIC HEATING ELEMENT OPERATING AT 110V DRAWS 10A TO BOIL A KETTLE
WATER IN 15 MINUTES. HOW MUCH ELECTRICAL ENERGY IS SUPPPLIED IN KWH ?"
ENERGY = 110 x 10 x .25 / ?"
 = .275KWH
A 220V MOTOR DRAWING 12A DEVELOPS 3 HP. WHAT IS ITS EFFICIENCY ?
EFF = 3 x 746 / 220 x ?"
 = 84.7%
A FLUORESCENT LAMP CARRIES A CURRENT OF .75 A WHEN DRIVEN BY A 117V SOURCE."
IF THE EFFICIENCY IS 13%, HOW MUCH USEFUL LIGHT POWER IS PRODUCED ?"
POWER OUT = ? x 117 x .75"
 = 11.4W
A FLUORESCENT LAMP CARRIES A CURRENT OF .75 A WHEN DRIVEN BY A 117V SOURCE."
IF THE EFFICIENCY IS 13%, HOW MUCH WASTE HEAT IS PRODUCED ?"
HEAT POWER = ? x 117 x .75
 = 76.3W
TYPE EQUATION NUMBER (1-12) REQUIRED TO SOLVE PROBLEM, PRESS ENTER
INCORRECT, USE EQUATION
 ----  PRESS ANY KEY TO CONTINUE
C8BM225,264NH5U12R45BD12BR30NH5U12R=
C8BM225,264NH5U12R25BD12BR20NH5U12R=
TYPE IN VALUE OF UNKNOWN (?), PRESS ENTER"
****   CORRECT ANSWER IS "
  ****
ANOTHER PROBLEM (Y/N)"
BOARD
S4U10R10D2L8D2R6D2L6D2R8D2L10"
U2R4U6L4U2R10D2L4D6R4D2L10
U10R9F1D4G1L7D4L2BU6BR2U2RR6D2L6BL2BD6
U10R9F1D4G1L2F4L3H4L2D4L2BU6BR2U2R6D2L6BL2BD6"
C10U10R10D2L8D2R6D2L6D2R8D2L10BR1BU1P10,10d
C1U2R4U6L4U2R10D2L4D6R4D2L10BR1BU1P1,1d
C2U10R9F1D4G1L7D5L2BU6BR2U2RR6D2L7BL2BD6BR1BU1P2,2d
C12S6U10R9F1D4G1L3F5L2H5L2D5L2BU6BR2U2R6D2L6BL2BD6BR1BU1P12,12d
C15R25
BM98,47C12
BM98,63"
BM91,50"
BM98,88"
BM98,104
BM91,91"
BM98,129
BM98,145
BM91,132
BM232,54C10"
BM251,54
BM232,94
BM251,94
C15NH10U15R50"
BM225,95
BM240,129C10
BM233,132"
BM240,145C10
BM386,47C1
BM379,50
BM386,63C1
BM386,88C1
BM379,91
BM386,104C1"
BM386,131C1"
BM386,146C1"
BM379,134"
C15NH10U32R50"
BM374,147"
BM515,54C2
BM534,54
BM515,95C2
BM534,95
BM527,128C2"
BM527,144"
BM518,131"